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author | Georg Brandl <georg@python.org> | 2006-09-24 12:35:40 +0000 |
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committer | Georg Brandl <georg@python.org> | 2006-09-24 12:35:40 +0000 |
commit | a6b9ce185eec7127082c7d26112730099fa738ba (patch) | |
tree | 173acbd5ef6975762fa533d76a2e7f8523570708 /Lib/test/test_future.py | |
parent | 1f2157896524c174f39143bc8e4c8dbf22027a24 (diff) | |
download | cpython-git-a6b9ce185eec7127082c7d26112730099fa738ba.tar.gz |
Fix a bug in the parser's future statement handling that led to "with"
not being recognized as a keyword after, e.g., this statement:
from __future__ import division, with_statement
(backport from rev. 51993)
Diffstat (limited to 'Lib/test/test_future.py')
-rw-r--r-- | Lib/test/test_future.py | 17 |
1 files changed, 17 insertions, 0 deletions
diff --git a/Lib/test/test_future.py b/Lib/test/test_future.py index f5462e204d..f67c692115 100644 --- a/Lib/test/test_future.py +++ b/Lib/test/test_future.py @@ -82,6 +82,23 @@ class FutureTest(unittest.TestCase): else: self.fail("expected exception didn't occur") + def test_parserhack(self): + # test that the parser.c::future_hack function works as expected + try: + exec "from __future__ import division, with_statement; with = 0" + except SyntaxError: + pass + else: + self.fail("syntax error didn't occur") + + try: + exec "from __future__ import (with_statement, division); with = 0" + except SyntaxError: + pass + else: + self.fail("syntax error didn't occur") + + def test_main(): test_support.run_unittest(FutureTest) |