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authorChristian Brueffer <christian@brueffer.de>2014-10-15 17:54:50 +0200
committerChristian Brueffer <christian@brueffer.de>2014-10-15 17:54:50 +0200
commit657c8b9106084ea284b3bd50f6edd6bfef880a50 (patch)
tree83f92d827975159341c37d9531405ab19a76cd05 /numpy/lib/arraysetops.py
parent2f1786306e696709481ccfc95b844d5aa2700b6d (diff)
downloadnumpy-657c8b9106084ea284b3bd50f6edd6bfef880a50.tar.gz
Add examples for intersect1d and union1d of more than two arrays.
The approach was suggested by Jaime Frio in issue #5179.
Diffstat (limited to 'numpy/lib/arraysetops.py')
-rw-r--r--numpy/lib/arraysetops.py10
1 files changed, 10 insertions, 0 deletions
diff --git a/numpy/lib/arraysetops.py b/numpy/lib/arraysetops.py
index 5c3b504de..d3b6119f4 100644
--- a/numpy/lib/arraysetops.py
+++ b/numpy/lib/arraysetops.py
@@ -241,6 +241,11 @@ def intersect1d(ar1, ar2, assume_unique=False):
>>> np.intersect1d([1, 3, 4, 3], [3, 1, 2, 1])
array([1, 3])
+ To intersect more than two arrays, use functools.reduce:
+
+ >>> from functools import reduce
+ >>> reduce(np.intersect1d, ([1, 3, 4, 3], [3, 1, 2, 1], [6, 3, 4, 2]))
+ array([3])
"""
if not assume_unique:
# Might be faster than unique( intersect1d( ar1, ar2 ) )?
@@ -421,6 +426,11 @@ def union1d(ar1, ar2):
>>> np.union1d([-1, 0, 1], [-2, 0, 2])
array([-2, -1, 0, 1, 2])
+ To find the union of more than two arrays, use functools.reduce:
+
+ >>> from functools import reduce
+ >>> reduce(np.union1d, ([1, 3, 4, 3], [3, 1, 2, 1], [6, 3, 4, 2]))
+ array([1, 2, 3, 4, 6])
"""
return unique(np.concatenate((ar1, ar2)))