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| author | Sebastian Berg <sebastian@sipsolutions.net> | 2012-10-21 18:34:04 +0200 |
|---|---|---|
| committer | Sebastian Berg <sebastian@sipsolutions.net> | 2012-10-21 18:37:38 +0200 |
| commit | 4b281479db093a55c010610ad287c75beb6da13b (patch) | |
| tree | 5dbf562060839089603db307e3d96ed4da240abf /numpy/core/numeric.py | |
| parent | fb64bbf12f2405b3dc97f7736ae3dc35daf615dc (diff) | |
| download | numpy-4b281479db093a55c010610ad287c75beb6da13b.tar.gz | |
API: Change isfortran to f-contig and not c-contig
This was a check for 1-d arrays, this is the generalization to
higher dimension if we allow higher dimensioal arrays to be both
f- and c-contiguous.
Diffstat (limited to 'numpy/core/numeric.py')
| -rw-r--r-- | numpy/core/numeric.py | 4 |
1 files changed, 2 insertions, 2 deletions
diff --git a/numpy/core/numeric.py b/numpy/core/numeric.py index 5f0474d3e..0d0babbac 100644 --- a/numpy/core/numeric.py +++ b/numpy/core/numeric.py @@ -538,7 +538,7 @@ def require(a, dtype=None, requirements=None): def isfortran(a): """ Returns True if array is arranged in Fortran-order in memory - and dimension > 1. + and not C-order. Parameters ---------- @@ -584,7 +584,7 @@ def isfortran(a): >>> np.isfortran(b) True - 1-D arrays always evaluate as False. + C-ordered arrays evaluate as False even if they are also FORTRAN-ordered. >>> np.isfortran(np.array([1, 2], order='FORTRAN')) False |